Published: April 25, 2011
CLEMSON, S.C. — On your mark.
Get set.
Go! Find the derivative of the following function: f′(x) = x8 sin 5x.
Welcome to a taste of the Clemson Calculus Challenge, an annual competition of some of the Southeast’s top high school juniors and seniors.
Math whizzes from the Carolinas, Georgia and Alabama competed for team and individual honors — including a pair of $500 scholarships for aspiring Clemson University students — at the event.
Nearly 300 students from 34 schools entered the April 15 competition, the largest in the eight years Clemson’s mathematical sciences department has sponsored the event.
“The quality and size of the competition has been growing each year,” said Shari Prevost, a senior lecturer in the department and organizer of the event. “The competition provides motivation for students to gain a deeper understanding of calculus. Teachers also like the contest because it provides a warmup for the ensuing College Board Advanced Placement Calculus AB exams.”
Students earned points based on a battery of tests. Individual calculus tests were administered in the morning with questions ranging from the “fairly routine” to the “very challenging.” Team competition — in which students band together to beat the clock — was held in the afternoon.
And sorry: no calculators allowed.
After the competition, students and teachers relaxed with a presentation on a research topic that required calculus as a prerequisite. This year’s talk, “What’s Inside? — Medical Imaging Meets Mathematics,” was given by Jack Cooper, a graduate student in mathematical sciences. The day ended with an awards ceremony.
Winners of the 2011 Clemson Calculus Challenge are:
Division 1, Individual
Division 1, Team
Division 1, School
Division 2, Individual
Division 2, Team
Division 2, School
Division 3, Individual
Division 3, Team
Division 3 School
Incidentally, the answer to the problem at the beginning of this story is: f′(x) = 8x7 sin 5x + 5x8 cos 5x by the product rule and the chain rule.
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